Class IX Math COnstruction

                                                         Class-- IX 

                                                        Math

                                                       Construction

1.Construct at APQR, given that QR = 3 cm, 2Q=45° and PQ + QR = 6 cm.

2.Construct a AABC such that BC = 4 cm, 2B=60° and AC-AB=2 cm.

3.Construct a triangle XYZ in which 2Y=30°, 2Z=90° and XY+YZ+ ZX = 11 cm.

4.Construct angles of following measurements and justify the construction.

(i) 30°(ii) 45°(iii) 15°(iv) 75°(v) 105°(vi) 135°.

5.Construct a triangle with perimeter 10 cm and base angles 60° and 45°. Write the steps of construction.

6.Construct a quadrilateral ABCD in which AB = 6.3 cm, BC=5.2 cm, CD=5.6 cm, DA=7.1 cm

and 2B=60° construct a triangle equal in area to this quadrilateral. Write the steps of construction.

7.Construct a triangle with base length 5 cm, the sum of other two sides is 7 cm and one base

angle is 60°.

8.Construct a triangle ABC whose perimeter is 12 cm and 2B=80°, C=60°. (Steps of construction

are not required).

Comments

Post a Comment

Popular posts from this blog

class 8 science paper

                                                   Class VIII                                                    Science Each question has four alternatives marked (a) (b)   (c)   (d) , but only one of these alternatives is the correct answer. Find the correct answer 1.       Which of the following metals does not react with atmospheric oxygen when left in open? (a)     Sodium     (b) calcium    (c)    gold     (d)    aluminium 2.         Which of the following non m...
Read more

class IX statics

                                                                Class IX-Mathematics                                                                Statistics  (HOTS) 1.Mean of the ten observations x1, x2, .... X10 is p. If each of the first five observations is increased by    5 and each of the next five observations is decreased by 5 then new mean is q. Find p - q.  2.  If M =4+X2+.X5/15 , then find the value of x1 -M/15 +  x2-M/15  +  x3 -M/15 +......+X15-M/15. 3.Find the length of the longest rod that can be placed in a room 30 m long, 24 m broad and 18 m high. 4.A man spends ₹1,800 monthly on an average for the first four months...
Read more

class 8 math practice paper

                                                                                   Class 8                                                                          Mathematics          ...
Read more